The correct statement with regard to `H_(2)^(+)` and `H_(2)^(-)` is :

Options

A. both `H_(2)^(+)` and `H_(2)^(-)` do not exist
B. `H_(2)^(-)` is more stabel than `H_(2)^(+)`
C. `H_(2)^(+)` is more stable than `H_(2)^(-)`
D. both `H_(2)^(+)` and `H_(2)^(-)` are equally stable

Answer

C

Explanation

`H_(2)^(+),(sigma 1 s^(1))`
`:.B.O.=1/2(1-0)=1/2`
`H_(2)^(-):(sigma 1s^(2))(sigma^(***)1s^(1))`
`:.B.O.=1/2(2-1)=1/2`
Even though the bond ordr of `H_(2)^(+)` and `H_(2)^(-)` are equal but `H_(2)^(+)` is more stable than `H_(2)^(-)` are equal but `H_(2)^(+)` is more stable than `H_(2)^(-)` as in th latter, an electron is present in the higher energy antibonding `(sigma^(***)1s)` orbital.