An aqueous solution containing 6.5 g of NaCl of 90% purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid NaoH. The volume of 1 M acetic acid required to neutralise NaOH obtained above is

Options

A. `2000 cm^(3)`
B. `100 cm^(3)`
C. `200 cm^(3)`
D. `1000 cm^(3)`

Answer

B

Explanation

Weight of NaCl`=6.5xx90/100=5.85g`
No. of equivalents of NaCl
`=("wt. of " Nacl)/("mol. Mass of" NaCl)=5.85/58.5=0.1`
No. of equivalents of NaOH obtained =0.1
`:.N_(NaOH)xxV_(NaOH)xxN_(CH_(3)COOH)xxV_(CH_(3)COOH)`
`implies0.1xx1000=1xxV_(CH_(3)COOH)`
`impliesV_(CH_(3)COOH)=100cm^(3)`