2 moles of `N_(2) O_(4 (g))` is kept in a closed container at 298 K and under 1 atm pressure . It is heated to 596 K when 20% by mass of `N_(2) O_(4 (g))` decomposes to `NO_(2)` . The resulting pressure is

Options

A. 2.4 atm
B. 1.2 atm
C. 4.8 atm
D. 2.8 atm

Answer

A

Explanation

`{:(, 2 N_(2) O_(4) to 4 NO_(2)), (" Initially " ,2 " "0) , ("At 596 K" , 2p " "4p), ("Finally" , 2-2p " "4p):}`
As given , `2p = (20 xx 2)/(100)`
2p = 0.4
`therefore p = 0.2` atm
Resulting pressure (P) = 2 - 2p + 4p
P = 2 +2 p
P = 2 + 2 (0.2) = 2.4 atm