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The emf of a galvanic cell constituded w...

The emf of a galvanic cell constituded with the electrodes `Zn^(2+)//Zn (-0.76V) and Fe^(2+)//Fe (-0.41V)` is

A

`-0.35V`

B

`+1.17V`

C

`+0.35V`

D

`-1.17V`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("cell") = E_(R.H.E) - E_(I.H.E)`
`E_("cell") = -0.41 - (-0.76) = +0.35V`
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