The process is spontaneous at the given temperature, if

Options

A. `Delta H" is " +ve and Delta S " is " -ve`
B. `Delta H " is " -ve and Delta S " is " +ve`
C. `Delta H " is " +ve and Delta S " is " +ve`
D. `Delta H "is " and DeltaS` is equal to zero.

Answer

B

Explanation

`Delta G = Delta H - T Delta S` (Gibbs energy equation)
When, `Delta H` is -ve, but `T Delta S` is `+ve rarr Delta G` will be (-ve) [Highly spontaneous].