Using MOT, compare `O_2^(+) and O_2^(-)` species and choose the incorrect option.

Options

A. `O_(2)^(-)` is less stable
B. Both `O_(2)^(+) and O_(2)^(-)` are paramagnetic
C. `O_(2)^(+)` have higher bond order than `O_(2)^(-)`
D. `O_(2)^(+)` is diamagnetic while `O_(2)^(-)` is paramagnetic .

Answer

D

Explanation

Molecular orbital configuration of `sigma1s^(2)"*"1s^(2)sigma2s^(2)sigma "*"2s^(2)sigma2p_(z)^(2) pi2p_(x)^(2)= pi2p_(y)^(2) pi "*"2p_(x)^(1)`
Bond order ` = 1/2 (10-5) = 2.5`
Number of unpaired electrons = 1 , hence paramagneticc
Molecular orbital configuration of `O_(2)^(-): sigma1s^(2) sigma^("*")sigma 2s^(2)sigma^"*"2s^(2) sigma 2p_(z)^(2)pi2p_(x)^2 = pi2p_(y)^(2) pi"*" 2p_(x)^(2)= pi"*"2p_(y)^(1)`
Bond order `=1/2 (10-7) = 1.5`
Number of unpaired electron = 1 , hence paramagnetic
Both `O_(2)^(+) and O_(2)^(-) ` are paramagnetic
`O_(2)^(+)` have higher bond order than `O_(2)^(-)`
`O_(2)^(-)` is less stable .