`25 cm^(3)` of oxalic acid completely neutralised 0.064 g of sodium hydroxide. Molarity of the oxalic acid solution is

Options

A. `Na_(2)g`
B. `Na_(3)PO_(4)`
C. `NaCl`
D. `Na_(2)SO_(4)`

Answer

C

Explanation

Flocculation value is inversely proportional to flocculation power .
For the flocculation of positively charged sol `PO_(4)^(3-)` ions hae minimum flocculation power while `Cl^(-)` will have maximum flocculation reaction :
` k = (2.303)/t log. ([A]_(0))/([A]) = (2.303)/(60) log. (100)/(12.5) = 0.0346 " min"^(-1)`
Now ` t_(1//2) = (0.693)/k = (0.693)/(0.0346) = 20 ` min