For the equilibrium: `CaCO_(3(s)) iff CaO_((s)) + CO_(2(g)) , K_p = 1.64` atm at 1000 K, 50 g of `CaCO_3` in a 10 litre closed vessel is heated to 1000 K. Percentage of `ĆaCO_3` that remains unreacted at equilibrium is (Given R=0.082 L atm `K^(-1) "mol"^(-1)`).

Options

A. 0.6 % glucose solution
B. 0.1 M glucose solution
C. 0.06 % glucose solution
D. 0.01 M glucose solution

Answer

B

Explanation

Molarity of 0.06 % (w/v) aqueous solution
of urea = `(0.06 xx 1000)/(60 xx1000) = 0.01 M `
As osmotic pressure `(pi) ` = CRT
` :. " " 0.01 ` M solutions of urea will isotonic with 0.01 M glucose solution .