When ` CH_2 = CH -O - CH_2 - CH_3` reacts with one mole of HI , one of the products formed is

Options

A. `0.693 xx 3 " M Min"^(-1)`
B. `0.0693 xx 4 " M min"^(-1)`
C. `0.0693 " M min"^(-1)`
D. `0.0693 xx 3 " M min"^(-1)`

Answer

B

Explanation

`underset ("Intial conc.") (12 M) overset (t_(1//2)) to 6M overset (t_(1//2))to 3M `
`t_(1//2) = 10 ` min
`k = (0.693)/10 = 0.693 "min"^(-1)`
As `t_(1//2)` is 10 min , after 20 minutes the concentration will be 3 M .
Hence , Rate ` = 0.693 xx 3 " M " min^(-1)`