1L to 2M `CH_(2)COOH` is mixed with 1L to 3M `C_(2)H_(5)OH` to form an ester.The rate of the reaction with respect to the initial rate when each solution is diluted with an equal volume of water will be

Options

A. 0.25 times
B. 2 times
C. 0.5 times
D. 4 times.

Answer

A

Explanation

(a) : `r = k[CH_(3)COOH][C_(2)H_(5)OH]`
`r_(i)` = k[2 M][3 M] …(i)
`r_(f) = k [(2 M)/(2)][(3 M)/(2)]` …(ii)
On dividing (ii) by (i), we get
`(r_(f))/(r_(i)) = (k[M][3/2 M])/(k[2 M][3 M]) = 0.25`
`:.` The rate of reaction becomes 0.25 times of initial rate.