If the circuit shown the value of I in ampere is

Options

A. 1
B. `0.60`
C. `0.4`
D. `1.5`

Answer

C

Explanation

Total `R=1.6+2.4 Omega =4 Omega`.
`therefore` Current `=(4V)/(4 Omega)=1 A`
`4i_(1)=6i_(2) " Since " i_(1)+i_(2)=i`
`therefore i_(2)=0.4A` and `i_(1)=0.6 A`.