A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is 0.885 cm and the overlapping area of the plates is `5cm^(2)`. The capacity of the unit is

Options

A. `1.06 pF`
B. `4 pF`
C. `6.36 pF`
D. `12.72 pF`

Answer

B

Explanation

The given arrangement of nine plates is equivalent to the parallel combination of 8 capacitors.
The capacity of each capacitor, `C=(epsilon_(0)A)/(d)`
`=(8.854xx10^(-12)xx5xx10^(-4))/(0.885xx10^(-2))=0.5 pF`
`therefore` The capacity of 8 capacitors = 8C
`=8xx0.5=4 pF`.