A certain current on passing through a galvanometer produces a deflection of 100 divisions . When a shunt of one ohm is connected , the deflection reduces to 1 division . The galvanometer resistance is

Options

A. `10Omega`
B. `9.9Omega`
C. `100Omega`
D. `99Omega`

Answer

D

Explanation

`iR=epsilonprop100` divisions.
`iR=epsilonprop1` division

`:. (R')/R = 1/100 rArr R' =R/100`
But `R'=(R)/(100)=(R*1)/(R+1)` as 1 and R are in parallel.
`rArr(1)/(100)=(1)/(R+1)rArrR=99Omega`.