The total energy stored in the condenser system shown in the figure will be

Options

A. `8muJ`
B. `16muJ`
C. `2muJ`
D. `4muJ`

Answer

A

Explanation

`3muFand6muF` are in series.
`therefore(3xx6)/((3+6))=2muF` is the total. This in parallel with `muF`. `therefore` Total capacitance in the circuit is `4muF`.
Q=CV.
`(1//2)QV`= Energy
`rArr(1//2)V^(2)C=(1//2)xx2^(2)xx4xx10^(-6)J=8muJ`.