the value of `|(3-isqrt2)^2/(1+i2)|` is equal to (i) `11/sqrt5` (ii)`18/sqrt7` (iii) `5/sqrt11` (iv) `13/sqrt3`

the value of |((3-i sqrt(2))^(2))/(1+i2)| is equal to (i) (11)/(sqrt(5)) (ii) (18)/(sqrt(7)) (iii) (5)/(sqrt(11)) (iv) (13)/(sqrt(3))

Rationalise the denominator of (i) 1/sqrt7 (ii) 1/(sqrt5 + sqrt3) (iii) 1/(sqrt7 -1) (iv) 1/(sqrt(7) - sqrt(6))

Rationalise the denominators of the following: (i) 1/(sqrt(7)) (ii) 1/(sqrt(7)-sqrt(6)) (iii) 1/(sqrt(5)+sqrt(2)) (iv) 1/(sqrt(7)-2)

Simplify : (i) (sqrt(5)+sqrt(2))^2 (ii) (sqrt(11)-sqrt(5))^2

Simplify : (i) (sqrt(5)+sqrt(2))^2 (ii) (sqrt(11)-sqrt(5))^2

Rationalise the denominators of the following:(i) 1/(sqrt(7)) (ii) 1/(sqrt(7)-sqrt(6)) (iii) 1/(sqrt(5)+sqrt(2)) (iv) 1/(sqrt(7)-2)

Rationalise the denominators of the following:(i) 1/(sqrt(7)) (ii) 1/(sqrt(7)-sqrt(6)) (iii) 1/(sqrt(5)+sqrt(2)) (iv) 1/(sqrt(7)-2)

find the values of a and b in each of the following (i) (5+2sqrt3)/(7+4sqrt3) = a-6sqrt3 (ii) (3-sqrt5)/(3+2sqrt5)= asqrt5-(19/11) (iii) (sqrt2+sqrt3)/(3sqrt2-2sqrt3)=2-bsqrt6 (iv) (7+sqrt5)/(7-sqrt5)-(7-sqrt5)/(7+sqrt5)=a+(7/11)bsqrt5

Rationalise the denominator of each the of the following : (i)(1)/(3+sqrt(5))" "(ii)(1)/(sqrt(5)-sqrt(3))" "(iii)(16)/(sqrt(41)+5)" "(iv)(30)/(5sqrt(3)+3sqrt(5))" "(v)(3-2sqrt(2))/(3+2sqrt(2))

Rationalise the denominator of each the of the following : (i)(1)/(3+sqrt(5))" "(ii)(1)/(sqrt(5)-sqrt(3))" "(iii)(16)/(sqrt(41)+5)" "(iv)(30)/(5sqrt(3)+3sqrt(5))" "(v)(3-2sqrt(2))/(3+2sqrt(2))