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A planet moving around sun sweeps area A...

A planet moving around sun sweeps area `A_(1)` in 2 days , `A_(2)` in 3 days and `A_(3)` in 6 days . Then the relation between `A_(1) , A_(2)` and `A_(3)` is

A

`3 A_(1) = 2 A_(2) = A_(3)`

B

`2 A_(1) = 3 A_(2) = 6 A_(3)`

C

`3 A_(1) = 2 A_(2) = 6 A_(3)`

D

`6 A_(1) = 3 A_(2) = 2 A_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

When a planet revolves around the sun , its areal velocity is constant .
`therefore (A_(1))/(t_(1)) = (A_(2))/(t_(2)) = (A_(3))/(t_(3))`
`(A_(1))/(2) = (A_(2))/(3) = (A_(3))/(6)`
`3 A_(1) = 2 A_(2) = A_(3)`
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