In this circuit , the value of `I_(2)` is

Options

A. 0.2 A
B. 0.3 A
C. 0.4 A
D. 0.6 A

Answer

C

Explanation

From figure ,
Voltage across all the three branches is the same .
`therefore 10 l_(1) = 15 l_(2) = 30 l_(3)`
or `l_(1) = 1.5 l_(2) " " … (i)`
`15 I_(2) = 30 I_(3)`
or `I_(3) = (1)/(2) I_(2) " " … (ii)`
Also `I = I_(1) + I_2 + I_3 `
`1.2 = 1.5 I_(2) + I_2 + (1)/(2) I_(2) " "` (Using (i) and (ii))
`= (3I_(2) + 2I_(2) + I_(2))/(2)`
`1.2 = 3 I_(2)`
`I_(2) = (1.2)/(3) A = 0.4 A`