The ratio of the magnetic dipole moment to the angular momentum of the electron in the `1^(st)` orbit of hydrogen atom is

Options

A. `e/(2m)`
B. `e/m`
C. `(2m)/e`
D. `m/e`

Answer

A

Explanation

Magnetic dipole moment of the electron in the `1^(st)` orbit is
`M = (eh)/(4pi m) " " … (i)`
Angular momentum of the electron in the `1^(st)` orbit is
`L = (h)/(2pi) " " … (ii)`
Divide (i) by (ii) , we get `(M)/(L) = (eh)/(4 pi m) xx (2pi)/(h) = (e)/(2m)`