A circular coil of radius 10 cm and 100 turns carries a current 1 A. What is the magnetic moment of the coil ?

Options

A. `3.142 A m^(2)`
B. `3.142xx10^(4)A m^(2)`
C. `3 A m^(2)`
D. `10^(4) A m^(2)`

Answer

A

Explanation

Here,
Radius, `r=10cm = 10xx10^(-2)m`
Number of turns, `N=100`
Current, `I=1A`
Area of the coil, `A= pi r^(2)`
Magnetic moment of the coil,
`M= NIA=NI pi r^(2)`
`= 100xx1xx3.142xx(10xx10^(-2))^(2)A m^(2)`
`= 3.142 A m^(2)`