A 10 kg metal block is attached to a spring of spring constant 1000 N `m^(-1)`. A block is displaced from equilibrium position by 10 cm and released. The maximum acceleration of the block is

Options

A. `200m s^(-2)`
B. `10m s^(-2)`
C. `0.1 m s^(-2)`
D. `100 ms^(-2)`

Answer

B

Explanation

Here,
Amplitude, `A=10cm= 0.1 m`
Spring constant, `k=1000N m^(-1)`
Mass, `m=10kg`
Maximum acceleration of the block is
`a_("max")=omega^(2)A= (kA)/(m)" " ( :'omega=sqrt(k/m))`
`= (1000N m^(-1)xx0.1m)/(10kg)=10ms^(-2)`