What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 volt ?

Options

A. `0.1227` Å
B. 12.27 Å
C. 0.001227 Å
D. 1.227 Å

Answer

D

Explanation

de Broglie wavelength of the electron accelerated through a potential difference of V volt is
`lambda=(12.27)/(sqrt(V))Å`
For `V=100` volt
`lambda=(12.27)/(sqrt(100))Å=1.227Å`