The maximum kinetic energy of emitted ph...

The maximum kinetic energy of emitted photoelectrons depends on

incident angle

potential

pressure

frequency

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The kinetic energy of the photoelectrons depends upon:

For a metal the maximum wavelength required for photoelectron emission is 340 nm, find the work function. If the radiation of wavelength 250 nm falls on the surface of the given metal. Find the maximum kinetic energy of emitted photo electrons in eV. Given Planck's constant = 6.625 xx 10^(-34) Js , velocity of light in vacuum is 3 xx 10^(8)ms^(-1) .

Light of wavelength 4700Å is incident on a metal plate whose work function is 2 eV. Then maximum kinetic energy of the emitted photoelectron would be

A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value, then the maximum kinetic energy of the emitted photoelectrons would become

Two monochromatic radiations of frequencies v_(1) and v_(2) ( v_(1) gt v_(2) ) and having the same intensity are, in turn, incident on a photosensitive surface to cause photoelectric emission. Explain, giving reason, in which case (i) more number of electrons will be emitted and (ii) the maximum kinetic energy of the emitted photoelectrons will be more.

The light photons of energy 1.5 eV and 2.5 eV are incident on a metallic surface of work function 0.5 eV, the ratio of the maximum kinetic energy of the photoelectrons is

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