The partlcles emitted 1n the decay of `""_(92)^(238)U` to `""_(92)^(234)U`

Options

A. 2 `alpha` and 2 `beta`
B. 1 `alpha` and 2 `beta`
C. 1 `alpha` and 1 `beta`
D. 2 `alpha` only

Answer

B

Explanation

`""_(92)^(238)U to ""_(92)^(234)U+ x ""_(2)^(4)alpha+ y ""_(-1)^(0)beta`
Using law of conservation of charges and masses.
238 = 234 + 4x or x = 1 and 92 = 92 + 2x - y or y = 2x = 2
Therefore, one `alpha` and two `beta` particles are emitted.