A linear objectof height 10 cm is kept in front of a concave mirror of radius of curvature 15 cm, at a distance of 10 cm. The image formed is

Options

A. magnified and erect
B. magnified and inverted
C. diminished and erect
D. diminished and inverted

Answer

B

Explanation

Object distance, u = -10 cm,
focal length, `f=(R)/(2)=(-15)/(2)= -7.5 cm`
By mirror formula, `(1)/(v)=(1)/(f)-(1)/(u)=(1)/((-7.5))-(1)/((-10))`
`(1)/(v)=(-25)/(750) implies v= -30 cm`
Magnification, `m=(-v)/(u)=-(-30)/(-10)=-3`
`:.` The image formed is real, magnified and inverted.