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The mass defect of ""(2)^(4)He is 0.03 ...

The mass defect of `""_(2)^(4)He` is 0.03 u. The binding energy per nucleon of helium (in MeV) is

A

69.825

B

6.9825

C

2.793

D

27.93

Text Solution

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The correct Answer is:
B
The mass defect of `"_(2)^(4)He, Deltam = 0.03 u`
`"The binding energy per nucleon" =(Deltam xx 931)/(4)MeV= (0.03xx 931)/(4)MeV= 6.9825 MeV`
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