The equivalent capacitance between A and B is,

Options

A. 150 pF
B. 50 pF
C. 300 pF
D. `(100)/(3)` pF

Answer

D

Explanation

As both of the 100 pF capacitors are in series in Figure I.
`:. C_(AB) (100xx100)/(100+100) = 50 pF`
In figure III two parallel resistance are in series with one resistance = 50 + 50 = 100 pF Now 100 pF and 50 pF are in series,
`:. C_(AB) (100 xx 50)/(100+50) = (100 xx 50)/(150) = (100)/3` pF