The given graph shows the variation of velocity (v) with position (x) for a particle moving along a straight line. Which of the following graph shows the variation of acceleration (a) with position (x)?

Options

A.
B.
C.
D.

Answer

A

Explanation

(a): v = -kx + c (given line with negative slope) `(dv)/(dt) =-k (dx)/(dt) rArr a = -k(-kx + c) = k^(2)x – kc` . and x = 0 `rArr` a = -ve and slope of a – x graph is positive.