A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

Options

A. `3.16 xx 10^(-34)` J s
B. `1.05 xx 10^(-34)` J s
C. `4.22 xx 10^(-34)` J s
D. `2.11 xx 10^(-34)` J s

Answer

B

Explanation

(b) :` DeltaE = 10.2 eV` represents transition from `n=1` to `n =2`
`Deltap = h/(2pi) = (6.6xx10^(-34))/(2xx3.14) = 1.05 xx 10^(-34)` J s.