One mole of `O_2` gas is heated at constant pressure starting at `27^@`C. How much energy must be added to the gas as heat to double its volume?

Options

A. 750 R
B. Zero
C. 1050 R
D. 450 R

Answer

C

Explanation

(c): Here, `V_(1) = V, V_(2) = 2V_(1)= 2V`
`T_(1) = 27^(@)C` = 300 K
According to Charle's law,
`(V_(1))/(T_(1)) = (V_(2))/(T_(2)) :. T_(2) = ((V_(2))/(V_(1))) xx T_(1) = 600` K
Heat absorbed by the gas ar constant pressure = `nCpDeltaT`
`= 1xx 7/2 R xx 300 = 1050` R.