If the plane `x + y +z=1` is rotated through `90^@` about its line of intersection with the plane `x - 2y + 3z=0,` the new position of the plane is

If the plane x + y + z =1 is routated through an angle 90^(@) about its line of intersection with the plane x - 2y + 3z =0, then the new position of the plane is

The plane x-y-z =2 is rotated through an angle 90^(@) about its line of intersection with the plane x + 2y + z=2. Then equation of this pane in new position is

The plane x-y-z=4 is rotated through an angle 90^(@) about its line of intersection with the plane x+y+2z=4 . Then the equation of the plane in its new position is

The plane x-y-z=4 is rotated through an angle 90^(@) about its line of intersection with the plane x+y+2z=4 . Then the equation of the plane in its new position is

The plane x-y-z=4 is rotated through an angle 90^(@) about its line of intersection with the plane x+y+2z=4 . Then the equation of the plane in its new position is

The plane x-y-z=4 is rotated through an angle 90^(@) about its line of intersection with the plane x+y+2z=4 . Then the equation of the plane in its new position is

The plane x-y-z=4 is rotated through 90^(@) about tits line of intersection with the plane x+y+2z=4. Find its equation in the new position,

The plane x-y-z=2 is rotated through 90^(@) about its line of intersection with the plane x+2y+z=2 . The distance of (-1,-2,-1) from the plane in the new position is lamda sqrt(6/7) . Then the value of lamda is equal to