For `xgt1`, show that: `2log_10x-log_x 0.01ge4`

For x>1, show that: 2log_(10)x-log_(x)0.01>=4

solve for x: 2log_10x-log_x(0.01)=5

Show that: |log_ba+log_ab|ge2

solve for x:2log_(10)x-log_(x)(0.01)=5

If xgt0 , then show that log(1+x)gt(x)/(1+x) .

Select the correct answer (MCQ) : (iv) The least value of the quantity 2log_(10)(x) - log_(x)(0.01)[x > 1] =

For x > 1 , the minimum value of 2 log_10(x)-log_x(0.01) is

For x > 1 , the minimum value of 2 log_10(x)-log_x(0.01) is