A non–uniform thin rod of length L is placed along x-axis as such its one of ends at the origin. The linear mass density of rod is `lambda=lambda_(0)x`. The distance of centre of mass of rod from the origin is :

A non-uniform thin rod of length L is palced along X-axis so that one of its ends is at the origin. The linear mass density of rod is lambda = lambda_(0)x . The centre of mass of rod divides the length of the rod in the ratio:

A rod of length L is placed along the x-axis between x=0 and x=L. The linear mass density is lambda such that lambda=a+bx . Find the mass of the rod.

If the linear density of rod of length 3 m varies as lambda=2+x then the distance of centre of gravity of the rod is………….

A rod of length 'l' is placed along x-axis. One of its ends is at the origin. The rod has a non-uniform charge density lambda= a, a being a positive constant. Electric potential at P as shown in the figure is -

A rod of length 'l' is placed along x-axis. One of its ends is at the origin. The rod has a non-uniform charge density lambda= a, a being a positive constant. Electric potential at P as shown in the figure is -

The mass per unit length of a non-uniform rod of length L is given by mu= lamdaxx2 ​, where lamda is a constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is :-

A thin rod of length 6 m is lying along the x-axis with its ends at x=0 and x=6m. Its linear density *mass/length ) varies with x as kx^(4) . Find the position of centre of mass of rod in meters.