On which curve does the perpendicular tangents drawn to the hyperbola `(x^2)/(25)-(y^2)/(16)=1` intersect?

Two perpendicular tangents drawn to the ellipse (x^(2))/(25)+(y^(2))/(16)=1 intersect on the curve.

The eccentricity of the hyperbola (x^(2))/(25)-(y^(2))/(16)=1 is

The locus of the point of intersection of perpendicular tangents to the hyperbola (x^(2))/(3)-(y^(2))/(1)=1 , is

IF the locus of the point of intersection of two perpendicular tangents to a hyperbola (x^(2))/(25) - (y^(2))/(16) =1 is a circle with centre (0, 0), then the radius of a circle is

Number of points on the ellipse (x^(2))/(25) + (y^(2))/(16) =1 from which pair of perpendicular tangents are drawn to the ellipse (x^(2))/(16) + (y^(2))/(9) =1 is

Number of points from where perpendicular tangents can be drawn to the curve (x^(2))/(16)-(y^(2))/(25)=1 is

Find the point 'P' from which pair of tangents PA&PB are drawn to the hyperbola (x^(2))/(25)-(y^(2))/(16)=1 in such a way that (5,2) bisect AB