[" Single Select Choice - Weekly Test Ea...

[" Single Select Choice - Weekly Test Eamcet Maths "],[" Q.31the coordinates of "(2sqrt(2),-3sqrt(2))" in the new "],[" system are "],[" 1) "0.(5sqrt(3),-7)],[" 2) "0.(-1.-5)],[" 3) "0.6sqrt(3),-5)],[" 4) "quad (7-sqrt(3))]

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(2sqrt(7))/(sqrt(5)-sqrt(3))

When (0,0) is shifted to (sqrt(7),2+sqrt(3)) the coordinates of P(5,5), Q(-2,4) and R(7,-7) in the new system are A, B, C . Then area of /_\ABC is:

(sqrt(3)-sqrt(5))(sqrt(3)+sqrt(5))/(sqrt(7)-2sqrt(5))

If 0ltxltpi and cosx + sinx =1/2 , then tanx is (1) (4-sqrt(7))/3 (2) -(4+sqrt(7))/3 ( 3) (1+sqrt(7))/4 (4) (1-sqrt(7))/4

Simplify: sqrt(7)-3/5sqrt(7)+2sqrt(7)

The square root of (7+3sqrt5) (7-3sqrt5) is (A) 4 (B) sqrt5 (C) 3sqrt5 (D) 2

(5sqrt(7)+2sqrt(7))(6sqrt(7)+3sqrt(7))=?

Simplify : sqrt(7)-3/5sqrt(7)+2sqrt(7)

Find the 5th term of the progression 1,((sqrt(2)-1))/(2sqrt(3)),\ ((3-2sqrt(2))/(12)),\ ((5sqrt(2)-7)/(24sqrt(3))),\ ddot