[C" is the centre of ellipse "(x^(2))/(25)+(y^(2))/(16)=1],[" one focus.Then the ratio of "CS" to semi "],[" major axis is "]

C is the centre of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 and S is one of the foci.The ratio of CS to semi major axis is

C is the centre of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 and S is one of the foci. The ratio of C S to semi major axis is

If C is the center of the ellipse 9x^(2)+16y^(2)=144 and S is a focus,then find the ratio of CS to the semi-major axis.

If C is the center of the ellipse 9x^2+16 y^2=144 and S is a focus, then find the ratio of C S to the semi-major axis.

If C is the center of the ellipse 9x^2+16 y^2=144 and S is a focus, then find the ratio of C S to the semi-major axis.

If C is the centre of the ellipse 9x^(2) + 16y^(2) = 144 and S is one focus. The ratio of CS to major axis, is

If C is the centre of the ellipse 9x^(2) + 16y^(2) = 144 and S is one focus. The ratio of CS to major axis, is

Find the maximum area of an isosceles triangle incribed in the ellipse (x^(2))/(25)+(y^(2))/(16)=1, with its vertex atone end of the major axis.

If C is centre of the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 and the normal at an end of a latusrectum cuts the major axis in G, then CG =