Place a coin on gramophone disc near its centre and set the disc into the rotation. As the speed of rotation increases, the coin will slide away from the centre of the disc. The motion of coin is due to

Coefficient of static friction between a coin and gramophone disc is 0.5. Radius of the disc is 8cm . Initially the centre of the coin is pi cm cm away from the centre of the disc. At what minimum frequency will it start slipping from there? By what factor will the answer change if the coin is almost at the rim? (Use g =pi^2ms^-2) .

A small coin of mass 40 g is placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular acceleration alpha="2 rad s"^(-2) . The coefficient of static friction between the coin and the disc is mu_(s)=3//4 and the coefficient of kinetic friction is mu_(k)=0.5. The coin is placed at a distance r=1m from the centre of the disc. The magnitude of hte resultant force on the coin exerted by the disc just before it starts slipping on the disc is :

A small coin of mass 40 g is placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular acceleration alpha="2 rad s"^(-2) . The coefficient of static friction between the coin and the disc is mu_(s)=3//4 and the coefficient of kinetic friction is mu_(k)=0.5. The coin is placed at a distance r=1m from the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is?

A coin kept on a rotating gramophone disc just beging to slip if its centre is at a distance of 8 cm from the centre of the disc .The angular velocity of the gramophone disc is then doubled , Through what distance , the coin should be shifted towards the centre , so that the coin will just slip ?

A coin kept on a horizontal rotating disc has its centre at a distance of 0.25 m from the axis of rotation of the disc. If mu is 0.2, then the angular velocity of the disc at which the coin willslip off, is

A coins kept on a horizontal rotating disc has its centre at a distance of 0.25 m from the axis of rotation of the disc .If mu is 0.2 , then the angular velocity of the disc at which the coion will slip off, (g=9.8m//s^(2))

A gramophone disc is set revolving in a horizontal plane at the rate of 33(1)/(2) revolutions per minute. It is found that a small coin placed on the disc will remain there if its centre is not more than 5 cm from the axis of rotation. Calculate the coefficient of friction between the coin and the disc [Hint : Centripetal force = m omega^(2)r= Frictional force = mu N=mu mg ]

A brass disc is rotating about its axis. If temperature of disc is increased then its