Consider a branch of the hypebola `x^2-2y^2-2sqrt2x-4sqrt2y-6=0` with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is (A) `1-sqrt(2/3)` (B) `sqrt(3/2) -1` (C) `1+sqrt(2/3)` (D) `sqrt(3/2)+1`

A vertex of a branch of the hyperbola x^(2)-2y^(2)-2sqrt(2)x-4sqrt(2)y-6=0 , B is one of the end points of its latuscrectum and C is the focus of the hyperbola nearest to the point A . Statement- 1 : The area of DeltaABC is ((sqrt(3))/(2)-1) sq. units. Statement- 2 : Eccentricity of the hyperbola is (sqrt(3))/(2) and length of the conjugate axis is 2sqrt(2) .

If A(1,-1,2),B(2,1,-1)C(3,-1,2) are the vertices of a triangle then the area of triangle ABC is (A) sqrt(12) (B) sqrt(3) (C) sqrt(5) (D) sqrt(13)

If x = 5+2sqrt6 , then the value of (sqrtx +frac(1)(sqrtx)) is (A) 2sqrt2 (B) 3sqrt2 (C ) 2sqrt3 (D) 3sqrt3

The length of the perpendicular drawn from the point (3,-1,11) to the line x/2=(y-2)/3=(z-3)/4 is (A) sqrt(33) (B) sqrt(53 (C) sqrt(66) (D) sqrt(29)

The shortest distance between the line yx=1 and the curve x=y^(2) is (A)(3sqrt(2))/(8) (B) (2sqrt(3))/(8) (C) (3sqrt(2))/(5) (D) (sqrt(3))/(4)

The equation of the base of an equilateral triangle ABC is x+y=2 and the vertex is (2,-1). The area of the triangle ABC is: (sqrt(2))/(6) (b) (sqrt(3))/(6) (c) (sqrt(3))/(8) (d) None of these

If the area of the triangle formed by the lines x=0,y=0,3x+4y-a(a>0) is 1, then a=(A)sqrt(6)(B)2sqrt(6)(C)4sqrt(6)(D)6sqrt(2)

The perimeter of the triangle formed by the points (0,0),(1,0) and (0,1) is 1+-sqrt(2) (b) sqrt(2)+1(c)3(d)2+sqrt(2)

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is sqrt((20)/(3)) (b) (2)/(sqrt(15))sqrt((8)/(15)) (d) sqrt((15)/(2))

If the angles of a triangle are in the ratio 4:1:1 then the ratio of the longest side to the perimeter is- sqrt(3):(2+sqrt(3)) b.1:sqrt(3)c1:2+sqrt(3)d.2:3