A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A metre and the separation ist metre. The dielectric constants are k, and k, respectively. Its capacitance in farad will be Q. 4 k k k,

A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A "metre"^(2) and the separtion is t metre. The dielectric constants are K_(1) and K_(2) , respectively. Its capacitance in farad will be

A parallel plate capacitor of plate area A and separation d filled with three dielectric materials as show in figure. The dielectric constants are K_1 , K_2 and K_3 respectively. The capacitance across AB will be :

A capacitor of plate area A and separation d is filled with two dielectrics of dielectric constant K_(1) = 6 and K_(2) = 4 . New capacitance will be

The space between parallel plate capacitors is filled with four dielectrics of equal dimensions but of dielectric constants K_(1), K_(2), K_(3)andK_(4) respectively. If K is the dielectric constant of a single dielectric that must be filled between capacitor plates to have the same capacitance between A and B. Then we must have

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

A capacitor of plate area A and separation between plates d is half filled with dielectric of dielectric constant K. What is equivalent capacitance?