R rarr R" is a function defined by "f(x)=10x-7" .If "g=f^(-1)" then "g(x)=

f:RrarrR is a function defined by f(x)=10x-7. If g=f^(-1) then g(x)=

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

If f:R rarr R is a function f(x)=x^(2)+2 and g:R rarr R is a function defined as g(x)=(x)/(x-1), then (i) fog (ii) go f

If f: R rarr R be defined by , f(x) = 10x - 7 and g = f^-1 , then g(x)

If f:R rarr R;g:R rarr R are functions defined by f(x)=3x-1;g(x)=sqrt(x+6) then the value of (gof^(-1))(2009) is

Let f:R rarr R , g : R rarr R be two function given by f(x) =5x-4 and g(x) = x^(3)+7 then (fog)^(-1) (x) equals

Let f : N rarr R be the function defined by f(x) = (2x-1)/(2) and g : Q rarr R be another function defined by g(x) = x + 2. Then (gof) ((3)/(2)) is