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Calculate the time required to beat 20kg...

Calculate the time required to beat `20kg` of water from `10^(@)C to 35^(@)C ` using an immersion heater `1000W` Assums that `8%` of the power input is used to bead the water specific beat capacity of water `= 4200J kg^(-1)K^(-1)`

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Calculate the time required to heat 20kg of water from 10^(@)C to 35^(@)C using an immersion heater 1000W Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200J kg^(-1)K^(-1)

Calculate the time required to heat 20kg of water from 10^(@)C to 35^(@)C using an immersion heater 1000W Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200J kg^(-1)K^(-1)

Calculate the time required to heat 20 kg of water from 10^(@)C to 35^(@)C using an immersion heater rated 1000 W. Assume that 80% of the power input is used to heat the water. Specific heat capacity of water =4200 J//kg-k

Calculate the time required to heat 20 kg of water from 10^(@)C to 35^(@)C using an immersion heater rated 1000 W. Assume that 80% of the power input is used to heat the water. Specific heat capacity of water =4200 J//kg-k

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What is the rice in temperature of 5 kg of water if it is given 84,000 J heat energy? Specific heat capacity of water =4200 J kg ^-1^@C^-1 .

Calcuate the heat required to convert 0.6 kg of ice at - 20^(@)C , kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given the specific heat capacity of ice =2100 j kg^(-1) K^(-1) , specific heat capacity of water =4186 j kg^(-1) K^(-1) latent heat ice =3.35xx10^(5) j kg^(-1) and latent heat of steam =2.256xx10^(6)j kg^(-1)