A closest distance of approach of an `a` particle travelling with a velocity `V` towards `Al_(13)` nucleus . `d` . The closest distacne of approach of an alpha particle travelling with velocity `4V` toward `Fr_(26)` nucleus is

A closest distance of approach of an "alpha" particle travelling with a velocity "v towards "Al(13)" nucleus is d The closest distance of approach of an alpha particle travelling with velocity 4V towards Fe(26) nucleus is

The closet distance of approach of an alpha -particle travelling with a velocity v to a certain nucleus is x.the distance of closet approach of alpha -particle travelling with a velocity 3 v to the same nucleus is

The closed distance of approach of an alpha- particle travelling with velocity V towards a stationary nucleus is d .For the closest distance to become (d)/(3) towards a stationary nucleus of double of the charge,the velocity of projection of the alpha- particle has to be

The closet distance of approach of an alpha - particle travelling with a velocity V towards a stationary nucles is .d.. For the closet distance to because d/3 towards stationary nucleus of double the charge the velocity of projection of the alpha - particle has to be

The closet distance of approach of an alpha - particle travelling with a velocity V towards a stationary nucles is .d.. For the closet distance to because d/3 towards stationary nucleus of double the charge the velocity of projection of the alpha - particle has to be

The distance of closest approach of an alpha particle gives an estimate of the size of the nucleus. Explain

Write the expression for distance of closest approach for a alpha -particle.