Among the given halides , which one will give same product in both `S_(N^(2))`and `S_(N^(2))`reaction

Among the given halides, which one will give same product in both S_(N^1) and S_(N^2) reactions.

Among the given halides, which will give same product in both S_N 1 and S_N 2 reactions(excluding stereoisomers)?

What is the product of the following S_(N^(2)) reaction ?

Which one of the lodine atoms will be more reactive in the S_(N)1 and S_(N)2 reaction ?

Which one of the lodine atoms will be more reactive in the S_(N)1 and S_(N)2 reaction ?

Consider the following statements : (1)Brideherated halides are inert towards both S_(N^(1)) and S_(N^(2)) reaction till one of the ring size is eoght member ring ) (2) The first step in both S_(N^(1)) and E_(1) reactions is the same (3) S_(N^(2)) reactions proceed with total retention of configuration (4) E_(2) elimination s are by the use of a solvent of low polarity and high concentration of a stromng base Which of the above statements are correct?

The correct decreasing order of reactivity for a given (R) group in both S_(N^(1)) " and " S_(N^(2)) reaction mechanism is :

Consider the following statements: (1) Bridgehead halides are inert towards both S_(N^1) and S_(N^2) reactions (till oneofthe ringsize is eight member ring) (2) The first step in both S_(N^2) and E_1 reactions is the same (3) S_(N^2) reactions proceed with total retention of configuration (4) E_2 eliminations are by the use of a solvent of low polarity and high concentration of a strong base Which of the above statements are correct?