A stone projected upwards with a velocity u reaches two points P and Q separated by a distance h with velocities `u//2` and `u//3`. The maximum height reached by it is

A body is thrown vertically upward with velocity u . The ratio of times at which it is at particular height h is 1 : 2 . What is the maximum height reached by the body above point of projection ?

An object is projected vertically upwards with a velocity u from the surface of the earth. Show that the maximum height reached by the object is h=(u^2R)/(2gR-u^2) where R is the radius of the earth. Calculate escape velocity from it.

A stone is projected with an initial velocity at some angle to the horizontal. A small piece separates from the stone before the stone reaches its maximum height. Then the piece will

For a body thrown vertically up with an initial velocity u ,the maximum height reached by body from the ground is

A stone is thrown upwards from the ground with a velocity u . What is the maximum height attained by the stone?

A stone is thrown vertically upwards with an initial velocity u form the top of a tower, recahes the ground with a velocity 3u. The height of the tower is

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

A body is projected vertically upwards with a velocity u from the top of a tower. Time taken by it to reach the ground is n times, then the time taken by it to reach the highest point in its path. Height of the tower is