A marble block of mass 2 kg lying on ice when given a velocity of `6m//s` is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is -

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is:

A marble block of mass 2 kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 10s. Then the coefficient of friction is (g = 10 ms^(-2) )