The system of simulataneous equations
`kx + 2y -z = 1`
`(k -1) y -2z = 2`
`(k +2) z = 3`
have a unique solution if k equals

For what values of k, does the system of linear equations x + y + z = 2, 2x + y - z = 3, 3x + 2y + kz = 4 have a unique solution ?

The simultaneous equations Kx+2y-z=1, (K-1)y-2z=2 and (K+2)z=3 have only one solution, when

The system of equation kx + y + z = 1, x + ky + z = k and x + y + kz = k^(2) has no solution if k equals :

What should be the value of k so that the system of linear equations x - y + 2z = 0, kx - y + z = 0, 3x + y - 3z = 0 does not possess a unique solution ?

What should be the value of k so that the system of linear equations x - y + 2z = 0, kx - y + z = 0, 3x + y - 3z = 0 does not possess a unique solution ?

The system of equations kx + y + z =1, x + ky + z = k and x + y + zk = k^(2) has no solution if k is equal to :

If the system of equations kx + y + 2z = 1 3x-y-2z = 2 -2x-2y-4z = 3 has infinitely many solutions, then k is equal to ________.

Under which one of the following condition does the system of equations kx + y + z = k - 1 x + ky + z = k - 1 x + y + kz = k - 1 have no solution ?