sin 2x (tan x + cot x)=2

tan^(2)2x + cot^(2)2x + 2tan 2x + 2 cot 2x=6

If sin^(2) x tan x + cos ^(2) x cot x - sin 2 x = 1 + tan x + cot x x in (0, pi) then x =

Solve : 2+tan x. cot\ (x)/(2)+cot x. tan\ (x)/(2)=0 .

1- (sin ^ (2) x) / (1 + cot x) - (cos ^ (2) x) / (1 + tan x) = sin x cos x

1- (sin ^ (2) x) / (1 + cot x) + (cos ^ (2) x) / (1 + tan x) = sin x cos x

If cos x = tan y , cot y= tan z and cot z= tan x, then sin x =

tan^(2)x + cot^(2)x =2

Prove that, cot x cos^(2)x -tan x sin^(2)x = 2 cot 2x

int( d x)/(sin ^(2) x cos ^(2) x) equals a) tan x+cot x+C b) tan x-cot x+C c) tan x cot x+C d) tan x-cot 2 x+C

int((cot x)/(sin x)-tan^(2)x-(tan x)/(cos x)+(2)/(cos^(2)x))dx