If `a^(3)+b^(3)+c^(3)=3abc and a+b+cne0 , ` then

If a, b, c are real, a^(3)+b^(3)+c^(3)=3abc and a+b+c ne 0 , then relation between a, b, c will be

If a, b c are real and a^(3)+b^(3)+c^(3) =3abc and a+b+c ne0 , then the relation between a, b,c will be

If a^(3) + b^(3) + c^(3)=3abc and a, b , c are distinct numbers. Which option is correct? (a) a+b+c= 0 (b) a= b= c

Find the HC.F of a^(3)+b^(3)+c^(3)-3abc and (a+b+c)^(3), given that ab+bc+ca=0

(a^(3)+b^(3)-c^(3)+3abc)/(a+b-c)=

If a/(b+c)=b/(c+a)=c/(a+b) and a+b+cne0 then show that a=b=c

If a/(b+c)=b/(c+a)=c/(a+b) and a+b+cne0 then show that a=b=c