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In the given figure, AB and CD are two equal chords. If O is the centre of the circle , `/_AOB= 120^(@)`, then find `/_OCD`.

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`AB=CD` given
`implies /_AOB=/_COD =120^(@)`
`=/_OCD = /_ODC=(180^(@)-/_COD)/(2)` `( :'CO=OD)`
`:. /_OCD=(180^(@)-120^(@))/(2)=30^(@)`
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