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In the figure (not to scale ), O is the ...


In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

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The correct Answer is:
`120^(@)`
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In the adjacent figure ( not to scale), O is the centre of the circle and /_OBA =30^(@) . Find /_ ACB . The following sentences ae the steps involved in solving the above problem. Arrange them in sequential order from the first to the last. (A) /_OAB =30^(@), /_ OBA =30^(@) implies /_ AOB =180^(@) -30^(@)-30^(@) =120^(@) (B) We known that /_ ACD =("Reflex "/_AOB)/(2)=(240^(@))/(2)=120^(@) (C ) Reflex /_ AOB =240^(@) (D ) OA =OB (radii) implies /_ OBA= /_ OAB =30^(@) .

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