In the above figure, bar(AF) || bar(ED),...

In the above figure, `bar(AF) || bar(ED),bar(CG) ||bar(AB)` and `bar(AE) ||bar(HD)` If `/_ FPD =40^(@)`, then `/_ AED =`

A

`40^(@)`

B

`80^(@)`

C

`120^(@)`

D

`140^(@)`

Text Solution

Verified by Experts

The correct Answer is:

D

(i) `(/_FPD` and `/_PDE` are alternate angles and are equal.
(ii) `/_ PDE` and `/_ AED` are interior angles on the same side of transversal and their sum is `180^(@)`.

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